How to break a list into chunks of N

Situatie

Method1:Using Yield

The yield keyword enables a function to comeback where it left off when it is called again

Backup

my_list = ['geeks', 'for', 'geeks', 'like',
           'geeky','nerdy', 'geek', 'love',
               'questions','words', 'life']
 
# Yield successive n-sized
# chunks from l.
def divide_chunks(l, n):
     
    # looping till length l
    for i in range(0, len(l), n): 
        yield l[i:i + n]
 
# How many elements each
# list should have
n = 5
 
x = list(divide_chunks(my_list, n))
print (x)

Output:

[['geeks', 'for', 'geeks', 'like', 'geeky'], 
 ['nerdy', 'geek', 'love', 'questions', 'words'], 
 ['life']]

Solutie

Method2: List comprehension
List comprehension is an elegant way to break a list in one line of code.

my_list = [1, 2, 3, 4, 5,

6, 7, 8, 9]

# How many elements each

# list should have

n = 4

# using list comprehension

final = [my_list[i * n:(i + 1) * n] for i in range((len(my_list) + n - 1) // n )]

print (final)

Output:

[[1, 2, 3, 4], [5, 6, 7, 8], [9]]

Tip solutie

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