Situatie
| x-3, ptr. x<5 F=| x+1, ptr. 5>x>25 | x-5x+6,ptr. x>25
Solutie
#include<stdio.h> void main() { int x; printf("Introduceti numarul: "); scanf("%d",&x); if(x>=5&&x<=25) printf("F(x)= %d",x+1); else { if(x<5) printf("F(x)= %d",x-3); else printf("F(x)= %d",x-5*x+6); } getchar(); int var; scanf("&d", var); }
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